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Look up the molecular weight of Lithium diisoproylamine and determine the amount of g of base needed for this experiment. Round to the hundredths place

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Answer:

0.72 g

Explanation:

Note that, the mass in gram of any substance is obtained from the relationship;

Mass= number of moles × molar mass

From the sequence of the reaction, the number of moles of Lithium diisopropylamide is 6.75mmol which is the same as 6.75 × 10^-3 moles

Molar mass of base= 107.1233 g/mol

Hence mass of the base is given by;

6.75 × 10^-3 moles × 107.1233 g/mol = 0.72 g

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