Answer:
d' = 0.86 mm
Explanation:
First we need to find the area of low power field:
A = πd²/4
where,
A = Area = ?
d = diameter = 1.5 mm
Therefore, using the value of diameter, we get:
A = π(1.5 mm)²/4
A = 1.767 mm²
Now, the new object occupies 1/3rd of this area:
A' = (1/3)A
πd'²/4 = (1/3)A
d'² = (4/3π) A
d'² = (4/3π)(1.767 mm²)
d' = √(0.75 mm²)
d' = 0.86 mm
