Answer:
C
Step-by-step explanation:
So we have the rational expression:
[tex]\frac{x^2-11x+30}{x^2-x-30}[/tex]
We can factor the numerator and the denominator:
Numerator:
[tex]x^2-11x+30[/tex]
Factor:
[tex](x-5)(x-6)[/tex]
Denominator:
[tex]x^2-x-30[/tex]
Factor:
[tex](x-6)(x+5)[/tex]
Substitute:
[tex]\frac{x^2-11x+30}{x^2-x-30}\\=\frac{(x-6)(x-5)}{(x-6)(x+5)}[/tex]
We can cancel out the (x-6). Thus:
[tex]=\frac{x-5}{x+5}[/tex]
Our answer is C.
