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The angle of elevation from a sailboat in a lake to the top of a vertical cliff is 60∘60∘. The sailboat is 210 feet from the foot of the cliff. How high is the cliff?

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olayemiolakunle65

Answer:

363.741 feet

Step-by-step explanation:

Let the height of the cliff be represented by x. Applying the appropriate trigonometric function, we have;

Tan θ = [tex]\frac{opposite side}{adjacent side}[/tex]

Tan [tex]60^{0}[/tex] = [tex]\frac{x}{210}[/tex]

cross multiply to have;

   x = 210 × Tan [tex]60^{0}[/tex]

      = 210 × 1.7321

      = 363.741

The cliff is 363.741 feet high.

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