Answer:
Explanation:
Total mass of sample = 20 g
mass of H = 1.34 g
mass of C = 8.00 g
mass of O = 20 - ( 8 + 1.34 )
= 10.66 g
no of atom of H in 1.34 g
= 1.34 / atomic weight of H .
= 1.34 / 1 = 1.34
no of atom of C in 8.00 g
= 8.00 / atomic weight of C
= 8.00 / 12 = .67
no of atom of O in 10.66 g
= 10.66 / atomic weight of O .
= 10.66 / 16 = .67
Ratio of no of atoms of H , C , O in the compound
= 1.34 : 0.67 : 0.67
Divide all by .67
= 2 : 1 : 1 ( integral ratio )
Hence empirical formula of compound
= CH₂O.
