Answer:
a) 45 bacteria
b) 12.27 hours
Step-by-step explanation:
\begin{aligned}
&105=C e^{2 k} \rightarrow C=\frac{125}{e^{2 k}} \rightarrow C=125 e^{-2 k}\\
&325=C e^{4 k}\\
&325=\left(125 e^{-2 k}\right) e^{4 k}\\
&325 / 125=e^{2 k}\\
&\ln (2.8)=2 k\\
&(\ln (2.8)) / 2=k\\
&k \approx .51481\\
&\begin{array}{l}
105=C e^{51481 *} \\
\frac{125}{e^{1.0396}}=C \\
C \approx 45
\end{array}\\
&B=45 e^{51481×(8)}\\
&B \approx 2765.95 \approx 2766\\
&25,000=45 e^{515 t}\\
&\frac{25,000}{45}=e^{.515 t}\\
&\ln \left(\frac{25,000}{45}\right)=.515 t\\
&\ln \frac{25,000}{45} / .515=t
\end{aligned}
t= 12.27 hours