Algebra help please

Answer:
[tex]=-p^3r^5[/tex]
Step-by-step explanation:
[tex]\left(-p\right)^3r^5\\\\\left(-p\right)^3\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}\\\\\left(-p\right)^3=-p^3\\\\=-p^3\\\\=-p^3r^5[/tex]