Any help with this please???? Running out of time!

Answer:
Step-by-step explanation:
[tex]Using\: A \: as\: a\: refernce\: angle ;\\Hypotenuse = 29\\Opposite =21\\Adjacent = 20\\\\Using \: SOHCAHTOA\\Sin A = \frac{Opposite}{Hypotenuse} \\\\Sin A = \frac{21}{29}[/tex]