Suppose you have a tablet with a capacity of gigabytes. For a plain text​ book, one byte typically corresponds to one character and an average page consists of 2000 characters. Assume all gigabytes are used for plain text books. a. How many pages of text can the tablet​ hold? b. How many​ 500-page books can the tablet​ hold?

Respuesta :

Answer:

a. 17,500,000 pages

b. 35,000

Explanation:

The computation is shown below:

As we know that

[tex]1 giga\ bytes = 1 \times 10 ^ {9} bytes[/tex]

So for 35 gigabytes it would be

[tex]= 35 \times 10 ^ {9} bytes[/tex]

And it is given that there is 2,000 characters

a. So the number of text pages would be

Let us assume that

for 2,000 it would be 1 page

So for [tex]35 \times 10 ^ {9} bytes[/tex] it would be x

Now we solve the x which is equal to

[tex]= \frac {35 \times 10 ^ {9} bytes}{2,000}[/tex]

= 17,500,000 pages

b. Now for 500 pages, it would be

[tex]= \frac{17,500,000}{500}[/tex]

= 35,000