Answer:
[tex]4.8t^3-10.4t[/tex]
Step-by-step explanation:
Well when you differentiate you use the exponent rule
let's say you have
[tex]f(x)=x^{n}\\ f'(x)=nx^{n-1}[/tex]
so we can use it separately
[tex]p=1.2t^4-5.2t^2\\p'=4(1.2)t^3-2(5.2)t\\p'=4.8t^3-10.4t[/tex]
