The graph of y=h(x)y=h(x)y, equals, h, left parenthesis, x, right parenthesis is a line segment joining the points (1,9)(1,9)left parenthesis, 1, comma, 9, right parenthesis and (3,2)(3,2)left parenthesis, 3, comma, 2, right parenthesis. Drag the endpoints of the segment below to graph y=h^{-1}(x)y=h −1 (x)y, equals, h, start superscript, minus, 1, end superscript, left parenthesis, x, right parenthesis.

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erinna erinna · Answer 1 · 2020-08-05T04:18:25+02:00

Answer:

End points of the this segment are (9,1) and (2,3).

Step-by-step explanation:

The given function is

[tex]y=h(x)[/tex]

End points of the this segment are (1,9) and (3,2).

If a function is defined as

[tex]f=\{(a,b),a\in R,b\in R\}[/tex] then

[tex]f^{-1}=\{(b,a),a\in R,b\in R\}[/tex]

It means, we have to interchange x and y-coordinates of the end points.

So, end points of the this segment are (9,1) and (2,3).

Plot these point and join them by a line segment.

aksnkj aksnkj · Answer 2 · 2021-11-17T11:52:26+01:00

The inverse of the function will be a line segment joining the points (9,1) and (2,3). See the graph.

Given information:

The function y=h(x) is a line segment joining the points (1,9) and (3,2).

So, the endpoints of the function y=h(x) can be written as,

[tex]y=h(x)=\{(1,9),(3,2)\}[/tex]

The inverse of a function is simply the opposite relation. In the inverse, the range and domain interchange themselves.

So, the inverse of the given function can be written as,

[tex]y=h^{-1}(x)=\{(9,1),(2,3)\}[/tex]

Refer to the graph of the function for more details.

For more details, refer to the link:

https://brainly.com/question/10300045