Answer:
the x-intercepts are -5 and 2
Step-by-step explanation:
[tex]y=2x^2+6x-20[/tex]
x-intercept is when y is set equal to zero
So, y = 0
[tex]0 = 2x^2+6x-20[/tex]
[tex]2x^3+6x-20 = 0\\Taking \ 2 \ common\\2(x^2+3x-10) = 0\\Dividing \ both \ sides \ by \ 2\\x^2+3x-10 = 0\\Using \ mid\ term \ break \ formula\\x^2+5x-2x-10 = 0\\x(x+5)-2(x+5)=0\\Taking \ (x+5) \ common\\(x+5)(x-2) = 0[/tex]
Either,
x+5 = 0 OR x-2 = 0
x = -5 OR x = 2
So, the x-intercepts are -5 and 2
Answer:
The x-intercepts would be (2, 0) and (-5, 0).
Step-by-step explanation:
To find the x-intercepts, substitute in 0 for y and solve for x.
0 = 2x^2 + 6x - 20.
Solve the equation.
x = 2, -5.
