Answer:
10
Step-by-step explanation:
[tex]\left(x-h\right)^{2}+\left(y-k\right)^{2}=r^2[/tex]
[tex]\left(x-6\right)^{2}+\left(y-0\right)^{2}=r^2\\[/tex]
We used (2,-3)
[tex]\left(2-6\right)^{2}+\left(-3-0\right)^{2}=25[/tex]
[tex]r^2=25\\[/tex] , so [tex]r = 5[/tex]
But this one is asking for the diameter, and to find it. It's simply 2r.
2*5 = 10