On January 22, 1943, in Spearfish, South Dakota, the temperature rose from −4.00°F to 45.0°F over the course of two minutes (the current world record for the fastest recorded temperature change). By how much did the temperature change on the Celsius scale?

Respuesta :

Answer:

The change on the Celsius scale is 27.22 °C.

Explanation:

The conversion of Fahrenheit to Celsius is the following:

[tex]T = \frac{5}{9}(^{\circ} F - 32)[/tex]

So, we need to convert T₁ and T₂ from °F to °C:

[tex]T_{1} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(- 4 - 32) = -20 ^{\circ} C[/tex]

[tex]T_{2} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(45 - 32) = 7.22 ^{\circ} C[/tex]

Hence, the change on the Celsius scale is:

[tex] \Delta T = T_{2} - T_{1} = 7.22 - (-20) = 27.22 ^{\circ} C [/tex]

Therefore, the change on the Celsius scale is 27.22 °C.

I hope it helps you!