Respuesta :
Answer:
a. True
b. False
c. True
d. False
Step-by-step explanation:
a. Meaning
as we can see that x is an element of Y
So notation is
[tex]x \in Y[/tex]
Therefore x is the subset of Y if each of an element of X is also an element of Y.
So notation is
[tex]X \subseteq Y[/tex]
2. (a) We need to proof
When [tex]A \subseteq B and B \subseteq C \so A \subseteq C[/tex]
We will say that A, B and C are the set that is [tex]A\subseteq B\ and\ B\subseteq C[/tex]
When A = ∅ then [tex]A\subseteq C[/tex] which shows true, as the set of empty is a subset of each set.
Hence, it is safe to say that A is not the empty set.
Now we will proof directly
Let us say x be an element of A
[tex]x \in A[/tex]
As [tex]A \subseteq B,[/tex] each of the element of A is also an element of B
[tex]x \in B[/tex]
As [tex]B \subseteq C[/tex], each if the element of B is also an element of C
[tex]x \in C[/tex]
Therefore, as we can see that each of an element of A is also known an element of C, that states [tex]A \subseteq C[/tex]
So, the given statement is true, as we conclude with a proof.
(b). We will assume {1}, B = {{1},2} and C = {{1},2,3}
As in the point a, which is an element of B, that is [tex]A \in B[/tex] which is true
As all of the elements in B are also an element in C, [tex]B \subseteq C[/tex] which is also correct.
Although, [tex]A \subseteq C[/tex] is false as 1 is an element of A that is not in C.
(c) We need to proof
When [tex]A \in B\ and \ B \subseteq C[/tex] then [tex]A \in C[/tex]
Let us assume that A, B and C are the sets that [tex]A\in B\ and\ B \subseteq C[/tex]
As, [tex]A \in B, \which\ is\ an\ element\ of\ the\ set\ B[/tex]
[tex]A\in B[/tex]
As, [tex]B \subseteq C[/tex], each of the element of B is also an element of C
[tex]A\in C[/tex]
So, its true.
(d) We will assume {1}, B = {{1},2} and C = {{1},2,3}
As in the point a, which is an element of B, that is [tex]A \in B[/tex] which is true
As {{1},2} is an element of B, [tex]B \in C[/tex] is correct
Although [tex]A \in C[/tex] is not correct as {1) is not an element in C.
SO the statement is false