Answer:
490,314
Step-by-step explanation:
This is a combinations problem. The formula is n!/(n-r)!xr!
This is 23!/(23-8)!x8!=
23!/15!x8!=
19,769,460,480/40,320=
490,314
Using the combination formula, it is found that the classes can be chosen in 490,314 ways.
The order in which the classes are chosen is not important, hence the combination formula is used to solve this question.
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this problem, 8 classes are chosen from a set of 23, hence:
[tex]C_{23,8} = \frac{23!}{8!(15)!} = 490314[/tex]
The classes can be chosen in 490,314 ways.
More can be learned about the combination formula at https://brainly.com/question/25821700
