Answer:
0.081
Step-by-step explanation:
To solve this question, we would use the z score formula
z score = (x-μ)/σ, where
x is the raw score = 36.32cm
μ is the population mean = 34.5 cm
σ is the population standard deviation = 1.3cm
z score = (36.32cm - 34.5cm)/1.3cm
z = 1.4
Using the normal distribution to find the z score for 1.4
P(z = 1.4) = 0.91924
Therefore, the probability that a boy has a head circumference greater than 36.32cm at birth is
P(x>36.32) = 1 - P(z = 1.4)
= 1 - 0.91924
= 0.080757
Approximately ≈ 0.081
