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If you weighed out 203 mg of the green chloro complex and dissolved it in 24.14 mL of acidic solvent, the molarity of your stock solution would be 0.0295 M. Using your precise value of mass and volume that you entered above, please enter your calculated value for the concentration of the original green chloro complex stock solution in moles per liter.
Mgreen stock =

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jamesesther1234

Answer:

0.00295M

Explanation:

Mass Concentration = mass/vol

= 0.203 g/ 0.02414 L = 8.409 g/L

But molarity = Mass conc / molar mass

∴ Molar mass(mol/L) = mass conc / molarity

= .84909 / 0.0295

= 285.06 g/mol

If 1 mol of green stock - 285.06g

? mol - 0.203 g

= 0.00071213 g

= 0.00071213 g / .2414L = 0.0095 mol/L.

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