Answer:
The shortest path to take is [tex]20\sqrt{3}\ cm[/tex] or [tex]34.64\ cm[/tex]
Step-by-step explanation:
This question requires an attachment (See attachment 1 for question)
Given
Cube Dimension: 20cm * 20cm
Required
Shortest path from A to B
For proper explanation, I'll support my answer with an additional attachment (See attachment 2)
The shortest path from A to B is Line labeled 2
But first, the length of line labeled 1 has to be calculated;
This is done as follows;
Since, the cube is 20 cm by 20 cm
[tex]Line1^2 = 20^2 + 20^2[/tex] (Pythagoras Theorem)
[tex]Line1^2 = 2(20^2)[/tex]
Take square root of both sides
[tex]Line1 = \sqrt{2(20)^2}[/tex]
Split square root
[tex]Line1 = \sqrt{2} * \sqrt{20^2}[/tex]
[tex]Line1 = \sqrt{2} * 20[/tex]
[tex]Line1 = 20\sqrt{20}[/tex]
Next is to calculate the length of Line labeled 2
[tex]Line2^2 = Line1^2 + 20^2[/tex] (Pythagoras Theorem)
Substitute [tex]Line1 = 20\sqrt{20}[/tex]
[tex]Line2^2 = (20\sqrt{2})^2 + 20^2[/tex]
Expand the expression
[tex]Line2^2 = (20\sqrt{2})*(20\sqrt{2}) + 20 * 20[/tex]
[tex]Line2^2 = 400*2 + 400[/tex]
Factorize
[tex]Line2^2 = 400(2+1)[/tex]
[tex]Line2^2 = 400(3)[/tex]
Take square root of both sides
[tex]Line2 = \sqrt{400(3)}[/tex]
Split square root
[tex]Line2 = \sqrt{400} * \sqrt{3}[/tex]
[tex]Line2 = 20 * \sqrt{3}[/tex]
[tex]Line2 = 20 \sqrt{3}[/tex]
The answer can be left in this form of solve further as follows;
[tex]Line2 = 20 * 1.73205080757[/tex]
[tex]Line2 = 34.6410161514[/tex]
[tex]Line2 = 34.64 cm[/tex] (Approximated)
Hence, the shortest path to take is [tex]20\sqrt{3}\ cm[/tex] or [tex]34.64\ cm[/tex]
