Abdur3379
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In a circle PQ & RS are two chords bisecting each other,prove that the two parts of one chord are equal to the two parts of the other.

Respuesta :

mathmate

Answer:

see proof below

Step-by-step explanation:

Let

p1,p2 = half lengths of chord p

q1,q2 = half length of chord q

By the intersecting chord theorem,

p1*p2 = q1*q2,    substituting p1=p2, q1=q2

p1^2 = q1*2

Take square-roots and reject negative roots

p1 = q1

therefore

p1=p2 = q1=q2, or

two parts of one chord are equal to the two parts of the other.

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