Which triangle congruence postulate can be used to prove that FEH=HGF?
SAS
HL
ASA
SSS

Answer:
Option (2).
Step-by-step explanation:
From the figure attached,
EFGH is a quadrilateral and FH is line which divides the quadrilateral into two right triangles, ΔFEH and ΔHGF.
In ΔFEH and ΔHGF,
Sides EH ≅ FG [Given]
FH ≅ FH [reflexive property]
ΔFEH ≅ ΔHGF [HL (Hypotenuse - length) postulate of congruence]
Option (2) will be the answer.