Answer:
The correct answer is option b)
50a+10b<1000; 200a+360b < 7200; a> 0; b>0
Step-by-step explanation:
We are given that Two kind of crated cargo namely A and B to be shipped by truck.
Cargo A:
Volume of each crate of cargo A = 50 cubic ft
Weight of each crate of cargo A = 200 pounds
Let number of crates of cargo A to be shipped = a
Total volume of 'a' crates of cargo A = 50a cubic ft
Total weight of 'a' crates of cargo A = 200a pounds
Cargo B:
Volume of each crate of cargo B = 10 cubic ft
Weight of each crate of cargo B = 360 pounds
Let number of crates of cargo B to be shipped = b
Total volume of 'b' crates of cargo B = 10b cubic ft
Total weight of 'b' crates of cargo B = 360b
Total volume allowed in the truck is 1000 cubic ft
Total volume of 'a' crates of Cargo A and Total volume of 'b' crates of Cargo B = 50a+10b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)
So, the inequality becomes
[tex]50a+10b<1000[/tex] ....... (1)
Total weight allowed (load limit) in the truck is 7200 pounds
Total weight of 'a' crates of Cargo A and Total weight of 'b' crates of Cargo B = 200a+360b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)
So, the inequality becomes
[tex]200a+360b<7200 ...... (2)[/tex] ....... (1)
And number of crates of cargo A and B are always a positive number.
So, a > 0 and b > 0.
So, the correct answer is option b.
b. 50a+10b<1000; 200a+360b < 7200; a> 0; b>0
