Answer:
[tex] \frac{13}{12}[/tex]
Step-by-step explanation:
[tex]p(5, \: \: 12) = (x, \: \: y) \\ \implies \: x = 5, \: \: y = 12 \\ \because \: {r}^{2} = {x}^{2} + {y}^{2} \\ \therefore \: {r}^{2} = {5}^{2} + {12}^{2} = 25 + 144 = 169 \\ \therefore \: {r} = \sqrt{169} \\ \therefore \: {r} = 13 \\ \because \cosec \theta = \frac{r}{y} \\ \therefore \cosec \theta = \frac{13}{12} \\ [/tex]
