Answer:
A'(7,3), B'(11,7) and C'(9,5).
Step-by-step explanation:
The vertices of given triangle are A(4,5), B(8,9), and C(6,7).
Given rule of translation is
[tex](x,y)\rightarrow (x+3,y-2)[/tex]
We need to find the vertices of triangle A'B'C'.
Now,
[tex]A(4,5)\rightarrow A'(4+3,5-2)=A'(7,3)[/tex]
[tex]B(8,9)\rightarrow B'(8+3,9-2)=B'(11,7)[/tex]
[tex]C(6,7)\rightarrow C'(6+3,7-2)=C'(9,5)[/tex]
Therefore, the vertices of triangle A'B'C' are A'(7,3), B'(11,7) and C'(9,5).
