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28-06-2020
Mathematics

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write a phythagoras triplet whose one is no. 17

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09pqr4sT 09pqr4sT

28-06-2020

8, 15, 17

[tex]2m, \: m^2-1, \: m^2+1[/tex]

17 can be expressed as [tex]16+1 = 4^2+1[/tex]

[tex]m=4[/tex]

[tex]2(4), \: (4)^2-1, \: (4)^2+1[/tex]

[tex]8, 16-1, 16+1[/tex]

[tex]8,15,17[/tex]

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