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A stone is dropped from a tower of height 3600cm.Find the velocity by which it strike the ground.Also,find the time taken to reach the ground.​

Respuesta :

gilbertazavedo72

Answer:

Explanation:

Here h=36m, a=g=10m/s, u=0

Use s=ut+(1/2)at^2

36=0*t+(10t^2)/2

time=2.68 sec

As from the formula of final velovity, v=(2gh)^1/2

v=(2*10*36)^1/2

v=(720)^1/2

v=26.83………This is the final velocity

tangletangle8

Answer:

Explanation:

s = vit + 1/2 gt*2

36 = 0 + 1/2 x 9.8 x t*2

t*2 = 7.34

t = 2.7sec

now,

2gs = vf*2 - vi*2

2 x 9.8 x 36 = vf*2 - 0

vf*2 = 705.6

vf = 26.5m/s

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