[tex]\frac{1}{xy^2}+\frac{x^2}{y}[/tex]
[tex]\frac{1}{xy^2}+\frac{x^3y}{xy^2}[/tex]
[tex]\frac{1+x^3y}{xy^2}[/tex]
Answer:
[tex] = \frac{1 + {x}^{3} y}{x {y}^{2} } \\ [/tex]
Step-by-step explanation:
[tex] \frac{1}{x {y}^{2} } + \frac{ {x}^{2} }{y} \\ \frac{1}{x {y}^{2} } + \frac{ {x}^{3} y}{x {y}^{2} } \\ = \frac{1 + {x}^{3} y}{x {y}^{2} } [/tex]
