Answer:
Since we know the zeroes of the function we can write:
y = a(x - 2)(x - 4) but we need to solve for a. Thankfully, we know that (0, 8) belongs to the line so we can plug these values in for x and y to solve for a. We get:
8 = a(0 - 2)(0 - 4)
8 = a * (-2) * (-4)
8 = 8a
a = 1 so the equation is y = 1(x - 2)(x - 4) or just y = (x - 2)(x - 4) for short.
Turning this into standard form we get y = x² - 6x + 8.
