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An orange of mass 3kg falls from a height 50m. When its height is H, its speed is
4m/s?
Write an expression that describes the conservation of energy with the given
numbers and H. You don't have to solve for H.

Respuesta :

MathPhys

Answer:

(10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s)²

Explanation:

Initially, the orange has only gravitational potential energy.

As the orange falls, it has a combination of potential energy and kinetic energy.

Energy is conserved, so initial energy = final energy:

PE₀ = PE + KE

mgH₀ = mgH + ½ mv²

gH₀ = gH + ½ v²

Plugging in values:

(10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s)²

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