En una fundición hay un horno eléctrico con capacidad para fundir totalmente 540 kg de cobre. Si la temperatura inicial del cobre es de 20º C ¿Cuántos kJ de energía calorífica en total se necesitan para fundir el cobre?

Respuesta :

Answer:

Q = 2.95*10^5 kJ

Explanation:

In order to calculate the energy required to melt the cooper, you first calculate the energy required to reach the boiling temperature. You use the following formula:

[tex]Q_1=mc(T_b-T_1)[/tex]     (1)

m: mass of cooper = 540 kg

c: specific heat of cooper = 390 J/kg°C

Tb: boiling temperature of cooper = 1080°C

T1: initial temperature of cooper = 20°C

You replace the values of the parameters in the equation (1):

[tex]Q_1=(540kg)(390\frac{J}{kg.\°C})(1080\°C-20\°C)=2.23*10^8J[/tex]

Next, you calculate the energy required to melt the cooper by using the following formula:

[tex]Q_2=mL_f[/tex]         (2)

Lf: melting constant of cooper = 134000J/kg

[tex]Q_2=(540kg)(134000\frac{J}{kg})=7.24*10^7J[/tex]

Finally, the total amount of energy required to melt the cooper from a temperature of 20°C is the sum of Q1 and Q2:

[tex]Q=Q_1+Q_2=2.23*10^8J+7.24*10^7J=2.95*10^8J=2.95*10^5kJ[/tex]

The total energy required is 2.95*10^5 kJ

Lanuel

The total energy required to melt the copper is equal to [tex]2.95 \times 10^5[/tex] Kilojoules.

Given the following data:

  • Mass of cooper = 540 kg
  • Initial temperature of cooper = 20°C

Scientifically, we know that:

  • Specific heat capacity of copper = 390 J/kg°C
  • Boiling temperature of copper = 1080°C
  • Melting constant of cooper = 134000J/kg

To calculate the total energy required to melt the copper:

First of all, we would determine the quantity of heat energy required to reach the boiling temperature of copper.

Mathematically, quantity of heat is given by the formula;

[tex]Q_b = mc\theta\\\\Q_b = 540 \times 390 \times (1080-20)\\\\Q_b = 210600 \times 1060\\\\Q_b = 2.23 \times 10^8 \;Joules[/tex]

Next, we would determine the quantity of heat energy required to melt copper.

[tex]Q_b = 540 \times 134000\\\\Q_b = 7.2 \times 10^6 \; Joules[/tex]

For total energy:

[tex]Q_T = Q_b + Q_m\\\\Q_T = 2.23 \times 10^8 + 7.24 \times 10^7\\\\Q_T = 2.95\times 10^8\\\\Q_T = 2.95\times 10^5\; Kilojoules[/tex]

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