Answer:
[tex]x = -24[/tex]
Step-by-step explanation:
Your question is not well presented
Given
[tex]\frac{2}{3}(\frac{1}{2}x + 12) = \frac{1}{2}(\frac{1}{3}x + 14) - 3[/tex]
Required
Solve for x
[tex]\frac{2}{3}(\frac{1}{2}x + 12) = \frac{1}{2}(\frac{1}{3}x + 14) - 3[/tex]
Open Brackets
[tex]\frac{2}{3}*\frac{1}{2}x + \frac{2}{3}*12 = \frac{1}{2}*\frac{1}{3}x +\frac{1}{2}* 14 - 3[/tex]
[tex]\frac{1}{3}x + \frac{2*12}{3} = \frac{1}{6}x +\frac{14}{2} - 3[/tex]
[tex]\frac{1}{3}x + \frac{24}{3} = \frac{1}{6}x +\frac{14}{2} - 3[/tex]
[tex]\frac{1}{3}x + 8 = \frac{1}{6}x +7 - 3[/tex]
Collect Like Terms
[tex]\frac{1}{3}x - \frac{1}{6}x= 7 - 3 - 8[/tex]
[tex]\frac{1}{3}x - \frac{1}{6}x= -4[/tex]
Take LCM
[tex]\frac{2-1}{6}x= -4[/tex]
[tex]\frac{1}{6}x= -4[/tex]
Multiply both sides by 6
[tex]6*\frac{1}{6}x= -4*6[/tex]
[tex]x= -4*6[/tex]
[tex]x = -24[/tex]
