Answer:
[tex]\tau=5.81\times 10^5p\ N-m[/tex]
Explanation:
We have,
Electric field, [tex]E=6.19\times 10^5\ N/C[/tex]
The electric dipole vector at an angle of 69.9 degrees from the direction of the field.
The torque acting on a molecule is given by :
[tex]\tau=p\times E\\\\\tau=pE\sin\theta[/tex]
p is electric dipole moment
[tex]\tau=p\times 6.19\times 10^{5}\times \sin (69.9)\\\\\tau=5.81\times 10^5p\ N-m[/tex]
So, the magnitude of the torque acting on the molecule is [tex]5.81\times 10^5p\ N-m[/tex].
