Answer:
0.003
Step-by-step explanation:
Given: A roulette wheel consists of 38 numbers 1 to 36, 0, and double 0.
Smith bets that the outcome will be one of the numbers 1 through 12.
To find: probability that Smith will lose his first 5 bets
Solution:
Probability refers to chances of occurrence of some event.
Probability = Number of favourable outcomes/Total number of outcomes
Total number outcomes = 38
As Smith bets that the outcome will be one of the numbers 1 through 12, number of favourable outcomes is equal to 12.
So,
probability that Smith will loss his first bet = [tex]\frac{12}{38}=\frac{6}{19}[/tex]
Therefore,
Probability that Smith will lose his first 5 bets = [tex](\frac{6}{19} )^5=0.003[/tex]
