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Complete the square to rewrite y=x^2-6x+14 in vertex form. Then state whether the vertex is a maximum or minimum and give is coordinates. A. - Minimum at (3,5) B. - Minimum at (-3,5) C. - Maximum at (-3,5) D. - Maximum at (3,5)

Respuesta :

CrazyMoosen

Answer:

3,5, Minimum

Step-by-step explanation:

y=x²-6x+14

y=(x²-2*3x +3²-3²)+14

y=(x²-2*3x+3²)+14-9

y=(x-3)²+5

a=1

p=3

q=5

a>0 ⇒ vertex is minimum

V(p,q) ⇒ V(3;5)

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