Step-by-step explanation:
Given that,
An equation [tex]11-4x=(3x-2)^2+1[/tex] in the standard form.
Solution,
[tex]11-4x=(3x-2)^2+1[/tex]
= [tex]11-4x=9x^2+4-12x+1\ \ \ [(a-b)^2=a^2+b^2-2ab][/tex]
[tex]11-4x=9x^2+4-12x+1\\\\11-4-1=9x^2-12x+4x\\\\6=9x^2-8x\\\\=9x^2-8x-6=0[/tex]
So, the standard form is given by option (D).
