ramirezmariamr1 ramirezmariamr1

31-08-2016
Mathematics

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How do you solve for lx-3l < 2 ?

Thank you

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Аноним Аноним

31-08-2016

[x-3]<2
We have to solve two inequations:
1)
x-3<2
x<2+3
x<5

2)
x-3>-2
x>-2+3
x>1

The solution wil be: 1<x<5 or (1,5).

Answer Link

31-08-2016

its identity that. |a|<X= -x<a<x
hence. |x-3|<2
-2<x-3<2
1<x<5
ie x lies b/w 1 and 5

Answer Link

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