W sklepie spożywczym jest 11,73 kg cukierków czekoladowych. Pierwszy klient kupił 48 dag cukierków. Drugi klient kupił 4/5 pozostałej ilości. Resztę cukierków, w równych ilościach, kupiło trzech ostatnich klientów. Po ile cukierków czekoladowych dostali ostatni klienci?

There is 11.73 kg of chocolate candies in the grocery store. The first customer bought 48 dag of candies. A second customer bought 4/5 of the remaining quantity. The last three customers bought the same amount of candy. How much chocolate did the last customers get?

Givens

The total amount of chocolate candies is 11.73 kilograms.
First costumer bought 48 dag of candies. (1 kg equals 100 dags)
Second costumer bougth 4/5 of the remaining.
Another three costumers bought the same amount of candy.

Let's transform 48 dag to kilograms.

[tex]48dag \times \frac{1kg}{100dag}= 0.48 \ kg[/tex]

Therefore, the first costumer bought 0.48 kilograms of candies.

The remaining amount is: [tex]11.73kg-0.48kg=11.25kg[/tex]

Now, we need to multiply the remaining amount of candies with 4/5

[tex]\frac{4}{5} \times 11.25kg=9 \ kg[/tex]

Therefore, the second costumer bought 9 kilograms of chocolate candies.

At last, we need to find the new remaining part of candies, which is

[tex]11.25-9=2.25 \ kg[/tex]

Therefore, the last costumers got 2.25 kilograms of chocolate candies.