Answer:
BC = [tex]\sqrt{12^{2} +12^{2} }[/tex]=12[tex]\sqrt{2}[/tex]
Step-by-step explanation:
if the triangle is ABC and have part 12
and right angle from B and have an angle 45 then the third angle is 45 too
then we have another part is 12
and the BC = [tex]\sqrt{12^{2} +12^{2} }[/tex]=12[tex]\sqrt{2}[/tex]
