Respuesta :
Answer:
610.3g
Explanation:
Zn:
m = 1.912
Zn : ZnI₂
1 : 1
1.912 : 1.912
ZnI₂:
m = 1.912 Mr = 65.4 + 2(126.9) = 319.2
mass = m×Mr:
mass = 1.912×319.2
mass = 610.3104 → 610.3g
The theoretical yield of Znl2, if 1.912 mol of zinc is used is 610.3g
Calculation of theoretical yield:
Since Zinc reacts with iodine in a synthesis reaction: Zn + I2 → Znl2
And, there is 1.912 mol of zinc
So,
Zn : ZnI₂
1 : 1
And,
1.912 : 1.912
For
ZnI₂:
m = 1.912 Mr = 65.4 + 2(126.9) = 319.2
Now
mass = m×Mr:
= 1.912×319.2
= 610.3104
= 610.3g
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