*WILL MARK BRAINLIEST FOR RIGHT ANSWER* How much current must be applied across a 60 Ω light bulb filament in order for it to consume 55 W of power? Show your work.

Respuesta :

Answer: The current must be equal to [tex]\frac{\sqrt{33} }{6}[/tex] amps, or ~0.9574 amps.

Explanation:

You can find the current in amperes using ohms and watts from this formula:

[tex]I = \sqrt{\frac{P}{R} }[/tex]

Where P represents power in watts, R represents resistance in ohms, and I represents current in amperes.

You can then substitute 60 and 55 into the equation to find I:

[tex]I = \sqrt{\frac{55}{60} } \\I = \frac{\sqrt{55} }{\sqrt{60} }[/tex]

Then, simplify the denominator:

[tex]I = \frac{\sqrt{55} }{2\sqrt{15} }[/tex]

Rationalize the denominator:

[tex]I = \frac{\sqrt{55} }{2\sqrt{15} } * \frac{\sqrt{15} }{\sqrt{15} } = \frac{\sqrt{825} }{30}[/tex]

Simplify the numerator by finding its factors:

[tex]I = \frac{5\sqrt{33} }{30} = \frac{\sqrt{33} }{6}[/tex]

The current must be equal to [tex]\frac{\sqrt{33} }{6}[/tex] amps, or ~0.9574 amps.