In a survey of students, 1162 stated they cheated and 2468 stated they did not. If one student is randomly selected what is the probability that they cheated

Respuesta :

Answer:

[tex] n = 1162 +2468 =3630[/tex]

And the probability that they cheated and we can use the classical definition of probability given by:

[tex] p =\frac{successes}{Total}[/tex]

And replacing we got:

[tex] p=\frac{1162}{3630}= 0.320[/tex]

So then the probability of people cheated is 0.320 or 32% approximately

Step-by-step explanation:

For this problem we know that in a survey of students, 1162 stated they cheated and 2468 stated they did not.

The total of people is given by:

[tex] n = 1162 +2468 =3630[/tex]

And the probability that they cheated and we can use the classical definition of probability given by:

[tex] p =\frac{successes}{Total}[/tex]

And replacing we got:

[tex] p=\frac{1162}{3630}= 0.320[/tex]

So then the probability of people cheated is 0.320 or 32% approximately