Respuesta :
Answer:
For this case we know that the total distance to travel is 325 mi. And we know that Aretha travels at the following velocity:
[tex] V = \frac{X}{t} = \frac{195 mi}{3 hr}= 65 \frac{mi}{hr}[/tex]
Then we can use the following definition:
[tex] D = Vt[/tex]
Where D is the distance and V the velocity. And solving for t we got:
[tex] t = \frac{D}{V}[/tex]
And replacing we got:
[tex] t = \frac{325 mi}{65 \frac{mi}{hr}}= 5[/tex]
So then we can conclude that after 5 hours at this rate Aretha will arrive to home
Step-by-step explanation:
For this case we know that the total distance to travel is 325 mi. And we know that Aretha travels at the following velocity:
[tex] V = \frac{X}{t} = \frac{195 mi}{3 hr}= 65 \frac{mi}{hr}[/tex]
Then we can use the following definition:
[tex] D = Vt[/tex]
Where D is the distance and V the velocity. And solving for t we got:
[tex] t = \frac{D}{V}[/tex]
And replacing we got:
[tex] t = \frac{325 mi}{65 \frac{mi}{hr}}= 5[/tex]
So then we can conclude that after 5 hours at this rate Aretha will arrive to home
