Answer:
S=288ft^2
Step-by-step explanation:
d=11.2ft, h=9.2ft
r=d/2=11.2/2=5.6
e=√r^2+h^2=√5.6^2+9.2^2
e=10.77ft
s=πr^2+πre
s=π(5.6)^2+π(5.6) (10.77)
s=91.67π
s≈288ft^2
If the slant height of the cone is 10.77 feet and the radius of the base circle is 5.6 feet. Then the surface area of the cone is 189.48 square feet.
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
The height of the cone is 9.2 feet and the diameter is 11.2 feet. Then the radius will be
r = d/2
r = 11.2/2
r = 5.6
Then the slant height of the cone will be
[tex]l = \sqrt{5.6^2 + 9.2}\\\\l = 10.77 \ \rm ft[/tex]
Then the surface area of the cone will be
[tex]\rm Surface \ area = \pi rl\\\\Surface \ area = \pi \times 5.6 \times 10.77\\\\Surface \ area = 189.48 \ ft^2[/tex]
More about the geometry link is given below.
https://brainly.com/question/7558603
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