The product of (x+p)(x+q) can be written as x^2+(p+q)x+pq.
An intermediate step in this multiplication is
x^2+px+qx+pq=x^2+(p+q)x+pq.
Explain why px+qx=(p+q)x.
I'm Really confused please help!

Respuesta :

Answer:

[tex]px+qx=(p+q)x[/tex] by taking out the common factors.

Step-by-step explanation:

It is given that the product of [tex](x+p)(x+q)[/tex] is [tex]x^2+(p+q)x+pq[/tex].

Given expression is

[tex](x+p)(x+q)[/tex]

Using distributive property, we get

[tex]x(x+q)+p(x+q)[/tex]

[tex]x(x)+q(x)+p(x)+p(q)[/tex]

[tex]x^2+qx+px+pq[/tex]

In middle terms px and qx the highest common factor is x. So taking out common factor from middle terms we get

[tex]x^2+x(q+p)+pq[/tex]

It can be written as

[tex]x^2+x(p+q)+pq[/tex]

Therefore, [tex]px+qx=(p+q)x[/tex] by taking out the common factors.