Answer: C
Step-by-step explanation:
[tex]\frac{3a}{4}+\frac{2a}{3}-\frac{a}{12}[/tex]
Find the least common denominator of 4, 3, and 12.
4-3-12 | 3
4-1-4 | 4
1-1-1 |-------- 12
The first fractions needs to be multiplied by 3, and the second fraction, by 4
[tex](\frac{(3a)*3}{(4)*3})+(\frac{(2a)*4}{(3)*4})-\frac{a}{12}[/tex]
Solve;
[tex]\frac{9a}{12}+\frac{8a}{12}-\frac{a}{12}[/tex]
Add the fractions with positive signs and subtract the one with negative sign.
[tex]\frac{(9a+8a)-a}{12}[/tex]
Solve;
[tex]\frac{17a-a}{12}=\frac{16a}{12}[/tex]
Simplify by 4;
16/4=4
12/4=3
[tex]\frac{4a}{3}[/tex]
