Answer:
Step-by-step explanation:
The complete question is attached.
The wall can be divided in two forms, a rectangle and a triangle. The base of the rectangle is 3 meters, and its height is 2 meters. The base of the triangle is 3 meters too, but its height is 1 meter.
Using the given information, we have
[tex]A=A_{rectangle} +A_{triangle}\\ A=(3m \times 2m )+ (\frac{1}{2} \times 3m \times 1m)\\A=6 \ m^{2} + 1.5 \ m^{2}=7.5 \ m^{2}[/tex]
The area of the wall is 7.5 square meters.
But, 1 can of paint can cover 24 square feet.
We know that 7.5 square meters are equal to 80.73 square feet. Then, we use the given relation between can of paint and the area they can cover
[tex]n=80.73\ ft^{2} \times \frac{1 \ can}{24 \ ft^{2} } \approx 3.4 \ cans[/tex]
Therefore, we need to use at least 4 cans to paint the wall.
