Answer:
[tex]V=22.4L[/tex]
Explanation:
Hello,
In this case, by using the ideal gas equation, er can compute the volume of fluorine gas as shown below:
[tex]PV=nRT\\\\V=\frac{nRT}{P}=\frac{1mol*0.082\frac{atm*L}{mol*K}+(0+273)K}{1.00atm} \\\\V=22.4L[/tex]
Best regards.
