contestada

In ΔQRS, the measure of ∠S=90°, the measure of ∠R=29°, and SQ = 5.8 feet. Find the length of RS to the nearest tenth of a foot.

Respuesta :

Answer:

10.5 ft

Step-by-step explanation:

In ΔQRS,

  • m∠S=90°
  • m∠R=29°,
  • SQ = 5.8 feet.

See the diagram below.

The triangle is a Right Triangle,

Using trigonometric ratios,

[tex]Tan R=\dfrac{|SQ|}{|RS|} \\Tan 29^\circ=\dfrac{5.8}{|RS|}\\$Cross multiply$\\|RS|XTan 29^\circ=5.8\\|RS|=\dfrac{5.8}{Tan 29^\circ}\\$=10.5 ft (to the nearest tenth of a foot)[/tex]

Ver imagen Newton9022

Answer:

10.5  

explain

x = 5.8 / tan 29 = 10.4635

10.5 feet

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