Answer:
x = [tex]\sqrt{13}[/tex]
Step-by-step explanation:
The segment from the vertex to the base is a perpendicular bisector.
Using Pythagoras' identity on the right triangle on the left.
x² = 2² + 3² = 4 + 9 = 13 ( take the square root of both sides )
x = [tex]\sqrt{13}[/tex]
