Answer:
2 Fe + 3 Cl2 -> 2 FeCl3
Explanation:
Write out the problem and list how many of each element are on each side.
__Fe + __Cl2 -> __FeCl3
Fe = 1 Fe = 1
Cl =2 Cl = 3
As Cl needs changing on the reactants side, put a 3 in the __ space and write the problem again.
__Fe + 3 Cl2 -> __FeCl3
Fe = 1 Fe = 1
Cl =6 Cl = 3
Now fix the products side.
__Fe + 3 Cl2 -> 2 FeCl3
Fe = 1 Fe = 2
Cl =6 Cl = 6
Now fix the reactants again.
2 Fe + 3 Cl2 -> 2 FeCl3
Fe = 2 Fe = 2
Cl =6 Cl = 6
Hope this helps!
